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Forums > C64 Coding > ROL'in a byte onto itself
2016-03-01 17:04
mhindsbo
Account closed

Registered: Dec 2014
Posts: 50
ROL'in a byte onto itself

What is the fastest and/or shortest code for rolling a pattern through a byte? I use it to trigger an action following a certain pattern. I came up with (18 cycles worst case / 12 bytes):
          clc
          lda pattern
          bpl no_carry
          sec
no_carry  rol pattern
          bcs take_action 

if your pattern ends on a 1 (bit 0 = 1) then you could also do (17 cycles worst case / 13 bytes)
          lda pattern
          bne @cont
          lda #%00110101   ; restore pattern
@cont     asl
          sta pattern
          bcs take_action 

any other variations?
2016-03-01 17:10
chatGPZ

Registered: Dec 2001
Posts: 11108
ldx pattern
lda table,x
sta pattern
2016-03-01 17:26
mhindsbo
Account closed

Registered: Dec 2014
Posts: 50
Like it. 15 cycles (once you add the branch to take action) and 19 bytes (incl. branch and 8 byte table) if I am correct. If you have different patterns then full page table.
2016-03-01 17:27
ChristopherJam

Registered: Aug 2004
Posts: 1378
Should be able to replace the first version with this?
    lda pattern
    asl a
    rol pattern
    bcs take_action
2016-03-01 17:39
mhindsbo
Account closed

Registered: Dec 2014
Posts: 50
indeed ... now why did I miss that ;-)
2016-03-01 18:47
Oswald

Registered: Apr 2002
Posts: 5017
my 2 cents:

cmp #$80 will put highest bit into carry aswell. useful if you dont want to destroy a.
2016-03-01 18:56
JackAsser

Registered: Jun 2002
Posts: 1989
Quote: my 2 cents:

cmp #$80 will put highest bit into carry aswell. useful if you dont want to destroy a.


Was just about to write it!!
2016-03-01 19:21
Hoogo

Registered: Jun 2002
Posts: 102
asl pattern
bcc no_action
inc pattern
2016-03-01 19:47
Peiselulli

Registered: Oct 2006
Posts: 81
asl
adc #$00
2016-03-01 23:16
ChristopherJam

Registered: Aug 2004
Posts: 1378
Hoogo wins \O/
2016-03-02 01:49
ChristopherJam

Registered: Aug 2004
Posts: 1378
I do like that (with a change of how the state is encoded) Groepaz' solution gives you arbitrary length sequences (as long as there are no more than 128 ones and no more than 128 zeros).

The table is contiguous, too—a fact that eluded me before I realised you could use a run of numbers ending with 127 for the zero states, and from 128 up for the ones (eg. use 128,125,126,129,127 to represent the sequence 10010)
 
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