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Forums > C64 Coding > Fast way to rotate a char?
2017-01-04 08:32
Rudi
Account closed

Registered: May 2010
Posts: 125
Fast way to rotate a char?

Im not talking about rol or ror, but swap bits so that they are rotated 90 degrees:

Example:

a char (and the bits can be random):
10110010 byte 1..
11010110 byte 2.. etc..
00111001
01010110
11011010
10110101
00110011
10110100
after "rotation" (rows and columns are swapped):
11001101
01011000
10100111
11111111
00101000
01010101
11011010
00100110
is it possible to use lookup tables for this or would that lookup table be too big?
or other lookuptable for getting and setting bits?

-Rudi
 
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2017-01-11 14:43
Oswald

Registered: Apr 2002
Posts: 5094
you just need a 64k table

lda byte1byte2
sta result

:)
2017-01-11 14:52
Rudi
Account closed

Registered: May 2010
Posts: 125
Colorbar: nice
Oswald: hah yeah, like thats gonna happen. :P
2017-01-11 16:52
Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336
Flip disk ...
Rotate monitor clockwise ...
2017-01-11 18:45
Oswald

Registered: Apr 2002
Posts: 5094
del.
2017-01-11 18:55
Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336
Quote: Flip disk ...
Rotate monitor clockwise ...


Girls They Want to Have Fun
2017-01-12 09:31
Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336
Quoting Rudi

2. swap lower nybbles of byte0->byte4, byte1->byte5 etc.

That helped. If all bits from block 'a' in my post above are put entirely in destination0, and the bits of the 4x2 block above that in destination1, nybbles have to be swapped at the end, but the code
sta selfmod:+1
and #$0f
sta destination0
selfmod:
lda moveHighNybbleToLowNybble,x
sta destination1

simplifies to just 'STA destination' and with this I can reduce the cycle count to 312, I think.
2017-01-13 09:05
ChristopherJam

Registered: Aug 2004
Posts: 1409
I'm not managing to get below 308 cycles (source and destination non zero page).

However, my second stage is only 23 cycles, less for when stage chaining is done. Perhaps this can help optimise one of the routines above?

#define swap1(s1,s2,m,d1,d2) \
    .(        :\
    lda s1    :\
    eor s2    :\
    sta ztb   :\
    and#m     :\
    eor s2    :\
    sta d1    :\
    eor ztb   :\
    sta d2    :\
    .)


(also - I could get down to 300 by moving the code to zero page, but then you'd have to jmp there and back, and couldn't unroll for multiple source/destinations - one char takes most of the page)
2017-01-13 10:32
Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336
Quoting ChristopherJam
I'm not managing to get below 308 cycles (source and destination non zero page).

However, my second stage is only 23 cycles.


Yes, thanks! That brings my lookup table approach down to 301 cycles when source and dest are in ZP and to 329 cycles when they are not.
2017-01-13 13:14
Axis/Oxyron
Account closed

Registered: Apr 2007
Posts: 91
Christopher: That 3x EOR thing is exactly what we did on Amiga back in the days. Didnt expect this to have an advantage on 6502. But where is the shifting taking place? Or is this only in 1 of the 3 passes, and the other pathes correct the bitorder with a table lookup?
2017-01-13 17:10
Rudi
Account closed

Registered: May 2010
Posts: 125
Color Bar: 301 cycles is nice, just 2 cycles more than what my code does.

If anyone can get below 299 cycles then pls explain what method you use :p
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