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2017-01-04 08:32

Rudi
Account closed

Registered: May 2010
Posts: 125

Fast way to rotate a char?

Im not talking about rol or ror, but swap bits so that they are rotated 90 degrees:

Example:

a char (and the bits can be random):

10110010 byte 1..
11010110 byte 2.. etc..
00111001
01010110
11011010
10110101
00110011
10110100

after "rotation" (rows and columns are swapped):

is it possible to use lookup tables for this or would that lookup table be too big?
or other lookuptable for getting and setting bits?

-Rudi

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2017-01-16 08:16

Pex Mahoney Tufvesson

Registered: Sep 2003
Posts: 52

> WOOT? ;o)

It's a new way of doing nothing; it's just a little too complicated for you Axis, so go back and play with your 300fps million-dots 6510 dot spheres. :P

---
Have a noise night!
http://mahoney.c64.org

2017-01-16 09:03

Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336

Quote: Quoting Color Bar

tya lda shuffle2,y

WOOT? ;o)

Lol. I needed some sleep. Honestly, this stuff is keeping me awake at night.

Pex: Good that you contribute something to this thread too.

2017-01-16 11:30

ChristopherJam

Registered: Aug 2004
Posts: 1409

Haha, you guys.

Um, my second and third shuffles from the first phase is pretty brute force on the tables front:

    ldx s1
    ldy s2
    lda sb_t2,x
    ora sb_t3,y
    sta d1
    lda sb_t0,x
    ora sb_t1,y
    sta d2

30 cycles with mem source, zp destination..

2017-02-01 21:22

Rudi
Account closed

Registered: May 2010
Posts: 125

nothing new here i guess..

2019-11-11 22:22

Krill

Registered: Apr 2002
Posts: 2980

Quoting Rudi

nothing new here i guess..

Almost 3 years later...

Pretty much what White Flame had in mind, i guess:
Quoting White Flame

Here's another idea which I think fails, but might be salvageable.

So the basic LSR, ROR accumulation grabs a bit and stores a bit, taking 2 instructions per bit. However, if done in-place just like many basic shift-add multiplication routines, ROR both sets a final bit as well as reads the next bit to place. This means that in dream land, the flip can be done in about 64 RORs. If fully in zp, that would be 320 cycles, but only 128 bytes of code with no tables.

However, the tactic I took doesn't seem to have a nice clean loop of RORs linking source bit locations to final bit locations. Various CMP #80s and other byte-masking & merging seems to be required, which would likely bloat it back up to 400+ cycles. But maybe by shuffling it around differently, an arrangement could be made that's both fast and short.

So (everything in zeropage):

               ; from:
         ; row7: a7 a6 a5 a4 a3 a2 a1 a0
         ; row6: b7 b6 b5 b4 b3 b2 b1 b0
         ; row5: c7 c6 c5 c4 c3 c2 c1 c0
         ; row4: d7 d6 d5 d4 d3 d2 d1 d0
         ; row3: e7 e6 e5 e4 e3 e2 e1 e0
         ; row2: f7 f6 f5 f4 f3 f2 f1 f0
         ; row1: g7 g6 g5 g4 g3 g2 g1 g0
         ; row0: h7 h6 h5 h4 h3 h2 h1 h0

               ; to:
dest7   .byte 0; a7 b7 c7 d7 e7 f7 g7 h7
dest6   .byte 0; a6 b6 c6 d6 e6 f6 g6 h6
dest5   .byte 0; a5 b5 c5 d5 e5 f5 g5 h5
dest4   .byte 0; a4 b4 c4 d4 e4 f4 g4 h4
dest3   .byte 0; a3 b3 c3 d3 e3 f3 g3 h3
dest2   .byte 0; a2 b2 c2 d2 e2 f2 g2 h2
dest1   .byte 0; a1 b1 c1 d1 e1 f1 g1 h1
dest0   .byte 0; a0 b0 c0 d0 e0 f0 g0 h0

transpose
                 ; cc  c    bits
row7 = * + 1
        lda #0   ; 2,       a7 a6 a5 a4 a3 a2 a1 a0
        asl      ; 2, a7 <- a6 a5 a4 a3 a2 a1 a0 00
        rol      ; 2, a6 <- a5 a4 a3 a2 a1 a0 00 a7
        rol row6 ; 5, b7 <- b6 b5 b4 b3 b2 b1 b0 a6
        rol      ; 2, a5 <- a4 a3 a2 a1 a0 00 a7 b7
        rol row5 ; 5, c7 <- c6 c5 c4 c3 c2 c1 c0 a5
        rol      ; 2, a4 <- a3 a2 a1 a0 00 a7 b7 c7
        rol row4 ; 5, d7 <- d6 d5 d4 d3 d2 d1 d0 a4
        rol      ; 2, a3 <- a2 a1 a0 00 a7 b7 c7 d7
        rol row3 ; 5, e7 <- e6 e5 e4 e3 e2 e1 e0 a3
        rol      ; 2, a2 <- a1 a0 00 a7 b7 c7 d7 e7
        rol row2 ; 5, f7 <- f6 f5 f4 f3 f2 f1 f0 a2
        rol      ; 2, a1 <- a0 00 a7 b7 c7 d7 e7 f7
        rol row1 ; 5, g7 <- g6 g5 g4 g3 g2 g1 g0 a1
        rol      ; 2, a0 <- 00 a7 b7 c7 d7 e7 f7 g7
        rol row0 ; 5, h7 <- h6 h5 h4 h3 h2 h1 h0 a0
        rol      ; 2, 00 <- a7 b7 c7 d7 e7 f7 g7 h7
        sta dest7; 3,       a7 b7 c7 d7 e7 f7 g7 h7
              ; = 58
       ;clc
row6 = * + 1
        lda #0   ; 2,       b6 b5 b4 b3 b2 b1 b0 a6
        and #$fe ; 2,       b6 b5 b4 b3 b2 b1 b0 00
        adc row6 ; 3, b6 <- b5 b4 b3 b2 b1 b0 00 a6
        rol      ; 2, b5 <- b4 b3 b2 b1 b0 00 a6 b6
        rol row5 ; 5, c6 <- c5 c4 c3 c2 c1 c0 a5 b5
        rol      ; 2, b4 <- b3 b2 b1 b0 00 a6 b6 c6
        rol row4 ; 5, d6 <- d5 d4 d3 d2 d1 d0 a4 b4
        rol      ; 2, b3 <- b2 b1 b0 00 a6 b6 c6 d6
        rol row3 ; 5, e6 <- e5 e4 e3 e2 e1 e0 a3 b3
        rol      ; 2, b2 <- b1 b0 00 a6 b6 c6 d6 e6
        rol row2 ; 5, f6 <- f5 f4 f3 f2 f1 f0 a2 b2
        rol      ; 2, b1 <- b0 00 a6 b6 c6 d6 e6 f6
        rol row1 ; 5, g6 <- g5 g4 g3 g2 g1 g0 a1 b1
        rol      ; 2, b0 <- 00 a6 b6 c6 d6 e6 f6 g6
        rol row0 ; 5, h6 <- h5 h4 h3 h2 h1 h0 a0 b0
        rol      ; 2, 00 <- a6 b6 c6 d6 e6 f6 g6 h6
        sta dest6; 3,       a6 b6 c6 d6 e6 f6 g6 h6
              ; = 54
       ;clc
row5 = * + 1
        lda #0   ; 2,       c5 c4 c3 c2 c1 c0 a5 b5
        and #$fc ; 2,       c5 c4 c3 c2 c1 c0 00 00
        adc row5 ; 3, c5 <- c4 c3 c2 c1 c0 00 a5 b5
        rol      ; 2, c4 <- c3 c2 c1 c0 00 a5 b5 c5
        rol row4 ; 5, d5 <- d4 d3 d2 d1 d0 a4 b4 c4
        rol      ; 2, c3 <- c2 c1 c0 00 a5 b5 c5 d5
        rol row3 ; 5, e5 <- e4 e3 e2 e1 e0 a3 b3 c3
        rol      ; 2, c2 <- c1 c0 00 a5 b5 c5 d5 e5
        rol row2 ; 5, f5 <- f4 f3 f2 f1 f0 a2 b2 c2
        rol      ; 2, c1 <- c0 00 a5 b5 c5 d5 e5 f5
        rol row1 ; 5, g5 <- g4 g3 g2 g1 g0 a1 b1 c1
        rol      ; 2, c0 <- 00 a5 b5 c5 d5 e5 f5 g5
        rol row0 ; 5, h5 <- h4 h3 h2 h1 h0 a0 b0 c0
        rol      ; 2, 00 <- a5 b5 c5 d5 e5 f5 g5 h5
        sta dest5; 3,       a5 b5 c5 d5 e5 f5 g5 h5
              ; = 47
       ;clc
row4 = * + 1
        lda #0   ; 2,       d4 d3 d2 d1 d0 a4 b4 c4
        and #$f8 ; 2,       d4 d3 d2 d1 d0 00 00 00
        adc row4 ; 3, d4 <- d3 d2 d1 d0 00 a4 b4 c4
        rol      ; 2, d3 <- d2 d1 d0 00 a4 b4 c4 d4
        rol row3 ; 5, e4 <- e3 e2 e1 e0 a3 b3 c3 d3
        rol      ; 2, d2 <- d1 d0 00 a4 b4 c4 d4 e4
        rol row2 ; 5, f4 <- f3 f2 f1 f0 a2 b2 c2 d2
        rol      ; 2, d1 <- d0 00 a4 b4 c4 d4 e4 f4
        rol row1 ; 5, g4 <- g3 g2 g1 g0 a1 b1 c1 d1
        rol      ; 2, d0 <- 00 a4 b4 c4 d4 e4 f4 g4
        rol row0 ; 5, h4 <- h3 h2 h1 h0 a0 b0 c0 d0
        rol      ; 2, 00 <- a4 b4 c4 d4 e4 f4 g4 h4
        sta dest4; 3,       a4 b4 c4 d4 e4 f4 g4 h4
              ; = 40
       ;clc
row3 = * + 1
        lda #0   ; 2,       e3 e2 e1 e0 a3 b3 c3 d3
        and #$f0 ; 2,       e3 e2 e1 e0 00 00 00 00
        adc row3 ; 3, e3 <- e2 e1 e0 00 a3 b3 c3 d3
        rol      ; 2, e2 <- e1 e0 00 a3 b3 c3 d3 e3
        rol row2 ; 5, f3 <- f2 f1 f0 a2 b2 c2 d2 e2
        rol      ; 2, e1 <- e0 00 a3 b3 c3 d3 e3 f3
        rol row1 ; 5, g3 <- g2 g1 g0 a1 b1 c1 d1 e1
        rol      ; 2, e0 <- 00 a3 b3 c3 d3 e3 f3 g3
        rol row0 ; 5, h3 <- h2 h1 h0 a0 b0 c0 d0 e0
        rol      ; 2, 00 <- a3 b3 c3 d3 e3 f3 g3 h3
        sta dest3; 3,       a3 b3 c3 d3 e3 f3 g3 h3
              ; = 33
row2 = * + 1
        lda #0   ; 2,       f2 f1 f0 a2 b2 c2 d2 e2
        asl      ; 2, f2 <- f1 f0 a2 b2 c2 d2 e2 00
        adc #$80 ; 2, f1 <- ?? f0 a2 b2 c2 d2 e2 f2
        rol row1 ; 5, g2 <- g1 g0 a1 b1 c1 d1 e1 f1
        rol      ; 2, ?? <- f0 a2 b2 c2 d2 e2 f2 g2
        cmp #$80 ; 2, f0 <- f0 a2 b2 c2 d2 e2 f2 g2
        rol row0 ; 5, h2 <- h1 h0 a0 b0 c0 d0 e0 f0
        rol      ; 2, f0 <- a2 b2 c2 d2 e2 f2 g2 h2
        sta dest2; 3,       a2 b2 c2 d2 e2 f2 g2 h2
              ; = 25
row1 = * + 1
        lda #0   ; 2,       g1 g0 a1 b1 c1 d1 e1 f1
        asl      ; 2, g1 <- g0 a1 b1 c1 d1 e1 f1 00
        adc #$80 ; 2, g0 <- ?? a1 b1 c1 d1 e1 f1 g1
        rol row0 ; 5, h1 <- h0 a0 b0 c0 d0 e0 f0 g0
        rol      ; 2, ?? <- a1 b1 c1 d1 e1 f1 g1 h1
        sta dest1; 3,       a1 b1 c1 d1 e1 f1 g1 h1
              ; = 16
row0 = * + 1
        lda #0   ; 2,       h0 a0 b0 c0 d0 e0 f0 g0
        cmp #$80 ; 2, h0 <- h0 a0 b0 c0 d0 e0 f0 g0
        rol      ; 2, h0 <- a0 b0 c0 d0 e0 f0 g0 h0
        sta dest0; 3,       a0 b0 c0 d0 e0 f0 g0 h0
               ; = 9
        rts    ; = 9 + 16 + 25 + 33 + 40 + 47 + 54 + 58 = 282

Thus...
Quoting ChristopherJam

Problem with bitshifter is it only deals with one bit at a time.

c2p exchanges four bitpairs in only 20-30 cycles. The expensive part is moving bits to matching positions within the two bytes they're being exchanged between...

Turns out both approaches are pretty much in the same ballpark. =)
(And this approach apparently coming out just ever so slightly faster. \=D/)

Might be possible to squeeze out a few more cycles here and there, so feel free.

I have a hunch that the general problem can't be solved in fewer than 280-ish cycles, though.

2019-11-12 10:21

JackAsser

Registered: Jun 2002
Posts: 2014

@Krill: Nice!!!

So, now what about the shortest code to rotate a char? (or a reference to the message number if it's already stated here)

2019-11-12 12:46

Krill

Registered: Apr 2002
Posts: 2980

Jackasser: Shortest? Going fully academic, eh? =D

I guess it would be the naïve approach, in a nested loop (untested):

SOURCE = $02
DEST   = $0a

        ldy #7      ; 2
-       ldx #7      ; 2
-       lsr SOURCE,x; 2
        ror         ; 1
        dex         ; 1
        bpl -       ; 2
        sax DEST,y  ; 2
        dey         ; 1
        bpl --      ; 2

15 bytes.

But i'd rather have a faster than 280-ish cycles approach. =)

2019-11-12 13:58

Oswald

Registered: Apr 2002
Posts: 5094

sax for giggles ?

2019-11-12 14:46

Krill

Registered: Apr 2002
Posts: 2980

SAX because STA zp,Y does not exist.

2019-11-12 15:35

Oswald

Registered: Apr 2002
Posts: 5094

*clapping*