initstabilise lda $d012 ldx #10 ; 2 - dex ; (10 * 5) + 4 bpl - ; 54 nop ; 2 eor $d012 - $ff,x; 5 = 63 bne initstabilise; 7 = 70 [...]; timer setup
Woah, this thread has been busy, nice work all :) Um, no need to blank the screen for my bracketing method. There's never character DMA on line $0ff, which is the only one for which there are 63 cycles for which an INC $d012 will read $ff and write $00. (assuming of course that I'm remembering correctly rumours that line $00 is only 62 cycles long - can anyone point me at documentation to confirm that? There's nothing in the venerable VIC Article [english], and I'm not spotting it anywhere on CodeBase either)
Btw, since the LDX #initval in Copyfault's method of post #90 is part of the init code, that one is only 9 bytes and hence the shortest unconstrained method.
I was just wondering of some W cycles within the init code might cause some kind of alignment on badlines, such that the first INC $d012 always appears on line $ff on a non-syncing cycle?
btw - with the various routines that have an entry point inside the loop, I was originally thinking "wait, aren't you then spending more bytes to branch into the start point?" but then I remembered that this code is probably running post decrunch, and most crunchers will happily let you set whatever start point you want, and kill CIA for you to boot.
btw - with the various routines that have an entry point inside the loop, I was originally thinking "wait, aren't you then spending more bytes to branch into the start point?" but then I remembered that this code is probably running post decrunch, and most crunchers will happily let you set whatever start point you want, and kill CIA for you to boot. Of course, if you're being this stingy with bytes there's a also fair chance you're *not* using an off the shelf decruncher...
loop: lax $9f ldy #$ff cmp <($100 + $9f - val),x bne loop+1
I do not know exactly how crunchers tailored to 6502 code work, but what will turn out to be the shortest crunched routine, could depend on the code or data around it, is that correct?
HH0c shx $HH00,Y HH0f lda #any_value HH11 bpl *-5
loop: lda $a6,x shx $00a0,y beq loop
entry: ldx $9e ldy #$00 beq loop