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Forums > C64 Coding > Shortest code for stable raster timer setup
2020-01-20 16:20
Krill

Registered: Apr 2002
Posts: 2940
Shortest code for stable raster timer setup

While working on my ICC 2019 4K entry (now postponed to ICC 2020, but i hope it'll be worth the wait), i came up with this (14 bytes):
initstabilise   lda $d012
                ldx #10          ; 2
-               dex              ;   (10 * 5) + 4
                bpl -            ; 54
                nop              ; 2
                eor $d012 - $ff,x; 5 = 63
                bne initstabilise; 7 = 70

                [...]; timer setup
The idea is to loop until the same current raster line is read at the very beginning (first cycle) and at the very end (last cycle) of a raster line, implying 0 cycles jitter.

With 63 cycles per line on PAL, the delay between the reads must be 63 cycles (and not 62), reading $d012 at cycle 0 and cycle 63 of a video frame's last line (311), which is one cycle longer due to the vertical retrace.

The downside is that effectively only one line per video frame is attempted, so the loop may take a few frames to terminate, and the worst case is somewhere just beyond 1 second.

The upside is that it always comes out at the same X raster position AND raster line (0), plus it leaves with accu = 0 and X = $ff, which can be economically re-used for further init code.

Now, is there an even shorter approach, or at least a same-size solution without the possibly-long wait drawback?
 
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2020-12-19 06:16
ChristopherJam

Registered: Aug 2004
Posts: 1403
Oh nice. There's always a use for a value pre-initialised to zero too, so I'm sure that would not be wasted.
2020-12-19 11:45
Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336
The choice of A&X can be much wider than s.t. A&X=1.
A&X=3 would also work to continue with the code after the BRK instruction. Or, if you store some useful data such as a small table after the BRK, it can be skipped with a larger value of A&X. Ideally the BRK instruction would serve as the first element of a table :-)
2020-12-19 22:13
Copyfault

Registered: Dec 2001
Posts: 468
Yes, you're both right, the BRK can be used as some data and the step from the beginning of the page to the adress where to continue can be chosen almost arbitrarily... but it imposes more (and weirder!!) restrictions on the choices for a and x;)

The example with A&X=1 was on intention, 'cause this way the $d0 turns into a BNE to the next opcode, and since A&X!=0, it's quite save to assume that the zero-flag is not set when the loop starts;))
2020-12-20 10:37
Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336
Quoting Copyfault
Yes, you're both right, the BRK can be used as some data and the step from the beginning of the page to the adress where to continue can be chosen almost arbitrarily... but it imposes more (and weirder!!) restrictions on the choices for a and x;)

Not more restrictions, you just have more choice.
2020-12-20 13:12
Copyfault

Registered: Dec 2001
Posts: 468
Quoting Rastah Bar
Quoting Copyfault
Yes, you're both right, the BRK can be used as some data and the step from the beginning of the page to the adress where to continue can be chosen almost arbitrarily... but it imposes more (and weirder!!) restrictions on the choices for a and x;)

Not more restrictions, you just have more choice.
Hmm, don't know, but the more bits are fixed by the AND-conditiion, the fewer variants for the pair (a,x) are permitted, no?
2020-12-20 13:26
Rastah Bar
Account closed

Registered: Oct 2012
Posts: 336
Yes, but the coder can choose to use A&X=1, or A&X=3, or something else. So in that sense there are less restrictions.
A priori he has more possibilities to choose from.

Some may not work, but he can always fall back to A&X = 1 or A&X = 3 if he can't make a data table work with the corresponding restrictions on A and X, and to A&X = 1 if A&X = 3 can't be met. Besides, A&X = 2^K, K = 2,...,7 also only fixes 1 bit.
2020-12-20 17:54
Copyfault

Registered: Dec 2001
Posts: 468
Ah, ok, looking from that meta-level I agree of course. The only case that causes trouble is A&X=2, everthing else will work.
2021-01-30 18:15
Krill

Registered: Apr 2002
Posts: 2940
Quoting Copyfault
Quoting Quiss
Neat! Right, no reason to make those two address bytes go to waste. :)

Another amusing thing to contemplate is how this code could be placed at, say, $08xx. Preferably without messing up the basic upstart.
[...]
Not necessarily the shortest piece of code, but it satisfies your requirement to have the sync routine at $08xx:
0843 A2 9E   LDX #$9E
0845 A0 08   LDY #$08
0847 E0 00   CPX #$00
0849 D0 F9   BNE $0844
Branching to $0844 leads to SHX $08A0,Y, so the operand byte of the CPX is altered continuously. As long as the "&(hi+1)" plays in, the compare operand will be =$08. When "&(hi+1)" disappears, the full $9E is written to the operand byte and the loop will end. This happens iff the critical SHX-cycle happens on a badline.
Nice trolljob there! =)

Took me a while and Rastah Bar's successive comment to figure out that code must sit at $08A3 instead, and not at $0843.
Seems to work nicely now in real-world code on realthing and x64sc, while on x64 the code just twiddles thumbs in an endless loop. =)
2021-01-30 20:43
Copyfault

Registered: Dec 2001
Posts: 468
Quote: Quoting Copyfault
Quoting Quiss
Neat! Right, no reason to make those two address bytes go to waste. :)

Another amusing thing to contemplate is how this code could be placed at, say, $08xx. Preferably without messing up the basic upstart.
[...]
Not necessarily the shortest piece of code, but it satisfies your requirement to have the sync routine at $08xx:
0843 A2 9E   LDX #$9E
0845 A0 08   LDY #$08
0847 E0 00   CPX #$00
0849 D0 F9   BNE $0844
Branching to $0844 leads to SHX $08A0,Y, so the operand byte of the CPX is altered continuously. As long as the "&(hi+1)" plays in, the compare operand will be =$08. When "&(hi+1)" disappears, the full $9E is written to the operand byte and the loop will end. This happens iff the critical SHX-cycle happens on a badline.
Nice trolljob there! =)

Took me a while and Rastah Bar's successive comment to figure out that code must sit at $08A3 instead, and not at $0843.
Seems to work nicely now in real-world code on realthing and x64sc, while on x64 the code just twiddles thumbs in an endless loop. =)


Oops, thought I corrected this in a later post, but it seems I forgot to.

However, other approaches have been discovered during the discussion that are comparable in size but more flexible regarding mem location.


So take my deep apologies... "trolljob" sounds really evil :(:(:(... and I really really did not intend to fool anyone.

Hopefully it won't happen again.
2021-01-30 21:27
Krill

Registered: Apr 2002
Posts: 2940
No worries, i actually took it for a mistake.

Though i wonder how that could happen, did you drunkenly type in some notes scribbled on a napkin, mistaking an A for a 4? =)
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